Wednesday 6 March 2013

Maths Assignment
















Method 1:

3cars=30
1car=30/3=10

1car+2pumpkins=20
10+2pumpkins=20
2pumpkins=20-10=10
1pumpkin=10/2=5

1car+1pumpkin+1clock=31
10+5+1clock=31
1clock=16

Method 2:

Let,
1car=x
1pumpkin=y
1clock=z

3x=30
x=30/3=10

x+2y=20
10+2y=20
2y=20-10=10
y=10/2=5

x+y+z=31
10+5+z=31
z=31-10-5=16

Thus the answers are as shown

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