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Chapter 4: Algebra Puzzle

__3*3 puzzle__
__My solution A__
*3 Umbrellas = 12*
**So 1 Umbrella = 4**
*1 Umbrella + 2 Flowers = 10*
*So 4 (Umbrella) + 6 =10*
*Since 6 = 2 Flowers*
**So 1 Flower = 3**
*1 Flower + 2 Clock = 33*
*So 3 (Flower) + 30 = 33*
*Since 30 = 2 Clock *
**So 1 Clock = 15**

__My solution B__
*Let a represent Umbrella*
*Let b represent Flower*
*Let c represent Clock*
*3a = 12*
*a = 12÷3*
**Therefore, a = 4**
*Since a +2b =10*
*4(a) + 2b =10*
*2b = 10 - 4*
*2b = 6*
*Therefore, b = 3*
*b +2c = 33*
*3 + 2c = 33*
*2c = 30*
*Therefore, c = 15*
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